Respuesta :

First we have to convert the equation to standard form to find its center and radius.

[tex] x^{2} -10x+ y^{2}-10y=-25 \\ \\ x^{2} -2(x)(5)+25 +y^{2}-2(y)(5)+25=-25+50 \\ \\ (x-5)^{2}+(y-5)^{2}=25 [/tex]

So, the center of the circle is (5,5) with radius equal to 5.

So, Draw the circle placing the center at (5,5) and with radius equal to 5.

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