Answer:
The pressure of the gas is 2.42atm.
Explanation:
The given information from the exercise is:
- Number of moles (n): 1.30 moles
- Volume (V): 13.0L
- Temperature (T): 295K
With the Ideal Gases Law formula we can calculate the pressure (P) of the gas, by replacing the values of n, V and T:
[tex]\begin{gathered} P*V=n*R*T \\ P*13.0L=1.30mol*0.082\frac{atm*L}{mol*K}*295K \\ P*13.0L=31.45atm*L \\ P=\frac{31.45atm*L}{13.0L} \\ P=2.42atm \end{gathered}[/tex]So, the pressure of the gas is 2.42atm.
