neangrattanaksopor neangrattanaksopor
  • 04-07-2021
  • Mathematics
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[tex]\frac{\frac{1}{a+1} }{a-\frac{1}{{a+\frac{1}{a}}{} } }[/tex] someone help please

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caylus
caylus caylus
  • 04-07-2021

Hello,

[tex]a\neq 0\\\\\dfrac{\dfrac{1}{a+1} }{a-\dfrac{1}{a+\dfrac{1}{a} }} \\\\\\=\dfrac{\dfrac{1}{a+1}}{\dfrac{a(a^2+1)+a} {a^2+1} }\\\\\\=\dfrac{a^2+1}{a(a+1)(a+2)}[/tex]

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