nicole5162 nicole5162
  • 01-11-2020
  • Physics
contestada

A 64.1 kg person is jogging at
2.93 m/s. How much KE does
the jogger have?
(Unit = J)

Respuesta :

Magzs Magzs
  • 01-11-2020

Answer:

275.15 J

Explanation:

Mass of the person = 64.1kg

Speed of person = 2.93m/s

Now,

K.E. = 1/2mv^2

.K.E. = 1/2*64.1*2.93*2.93

K.E. = 275.15 J

Answer Link

Otras preguntas

The line segment s bisects the angle C so that the two angles labeled x are equal. Show that the length of this angle bisector is s= 2abcosx/a + b
Y=1.40x 14.25 solving for x
The fare came to $42. for jordyn's taxi ride, which
WILL UPVOTE THE RIGHT ANSWER!!!! I ONLY HAVE 25 MINUTES LEFT The passage below is an excerpt from Robert Owen's A New View of Society (1813-1816). Use the passa
Hello can someone help me pls
Which statement correctly describes the difference between meiosis I and meiosis II? A) Meiosis I brings together sister chromatids, and meiosis II separates t
The population of foxville is about 12 times 10 to the power of 3. which is another way to write this number
Team infinite dimensions canoed 15 3/4 miles in 3 hours. what was their average rate of speed in miles per hour?
What is the coefficient of the term 5/3 xy ?
The cruising speed of a boeing 747 is 250 m/s. at this rate what distance does it travel in one minute?