Dimajago Dimajago

03-07-2020
Mathematics

contestada

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

Respuesta :

EpicMinion900 EpicMinion900

03-07-2020

Answer:

21

Step-by-step explanation:

The 5 smallest prime numbers are 1, 2, 3, 5, and 7.

So when multiplied it equals 105.

Divide by 42 and you get 2 21/42

So you have a remainder of 21

Answer Link

Otras preguntas

the 5th out of 10 questions

what two ordered pairs will show both intercepts for y=6x-5

If it takes a total of 6 hours to fill up an inground backyard pool using a standard hose. A function can represent this situation to represent the amount of wa

Darlus and____ were two Persian leaders who tried to conquer Greece

solve for y (6+y)h=c

A number, y, is equal to twice the sum of a smaller number and 3. The larger number is also equal to 5 more than 3 times the smaller number. Which equations rep

This 69-year-old female presents to the laboratory after her physician ordered quantitative and qualitative assays for troponin to assist in the diagnosis of he

What is the value of??? Please don’t just pick one....it needs to be right! Thanks

A solution is made by dissolving 3.8 moles of sodium chloride (NaCl) in 185 grams of water. If the molal boiling point constant for water (Kb) is 0.51 °C/m, wha

[tex] (8 + 5\sqrt{x} -98) - ( 3 + 6\sqrt{x-32) [/tex]