A residential complex has left for the recreation area a circular-shaped extension of 40 m radius. In this space, a basketball court 30 m long by 15 m wide will be built. Also, a trapezoid-shaped park will be left in the sand, 6 m with a larger base, 4 m with a lower base and 3.5 m in height. What is the area left in the circular zone, after building the basketball court and the sand park? NOTE: remember the value of π = 3.14

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saraharif006 saraharif006 · Answer 1 · 2020-07-01T15:18:54+02:00

Answer:

Step-by-step explanation:

Area of the circular zone = [tex]\pi[/tex]r^2

= 3.14 × 40^2 = 3.14 × 1600 = 5024 m^2

Area of the basketball court = l × b

= 30 × 15 = 450 m^2

Area of the trapezium shaped park = ( 6 + 4 ) 3.5 / 2

= 35/2 = 17.5 m^2

∴ Area left in the circular zone = Area of the circular zone - ( Area of the basketball court + Area of the trapezium shaped park )

= 5024 - ( 450 + 17.5 )

= 5024 - 467.5

= 4556.5 m^2

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