adipalmer adipalmer
  • 01-11-2019
  • Mathematics
contestada

Show that in a quadrilateral ABCD, AB+BC+CD+DA<2(BD+AC)

Respuesta :

Rishi2005
Rishi2005 Rishi2005
  • 01-11-2019

Step-by-step explanation:

We know that the length of the diagonals will be more than the side.

Lets suppose the quadrilateral is a rectangle, with sides 6 and 4.

The length of a diagonal is:

√(6*6)+(4*4)

√36+16

√52

7.21(rounded off to 3 sig. fig.)

So, 6+4+6+4<2(7.21+7.21)

20< 2*14.42

20<28.84, which is true.

:)

Answer Link

Otras preguntas

What did Upton Sinclair do to prepare for writing The Jungle? Select all that apply. A He studied details about working in a slaughterhouse. B He studied deta
Approximately how much of the Ottoman Empire was lost by 1914?
which setense is tje best example of a summary, rather than an evaluation? A. despite Davidson's claims,his idea are unlikely to have practical applications.B.D
What is the remainder when (x4 + 36) is divided by (x2 – 8)? 36
How much time does 18 goes into 626
with the issuance of the Monroe Doctrine, was America a world power? explain your reasoning
What is the main difference between informational listening and critical listening? in 125 words or more
Please help with this geometry hw!!
I really need help!!!
Please need this question answered asap