helpmeimgoingtocry helpmeimgoingtocry
  • 02-09-2019
  • Mathematics
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1/R + 1/JK=5C solve for 'J' please include how you solved it.

Respuesta :

znk
znk znk
  • 02-09-2019

Answer:

[tex]J = \dfrac{R}{5KRC - K}}[/tex]

Step-by-step explanation:

[tex]\begin{array}{rcll}\dfrac{1}{R} + \dfrac{1}{JK} & = & 5C &\\\\JK + R & = & 5JKRC & \text{Multiplied every term by JKR}\\JK & = & 5JKRC - R & \text{Subtracted R from each side}\\JK - 5JKRC & = & -R & \text{Subtracted 5JKRC from each side}\\J(K - 5KRC) & = & -R & \text{Removed the common factor J}\\J & = & -\dfrac{R}{K - 5KRC} & \text{Divided each side by (K - 5KRC)}\\\\J & = & \mathbf{\dfrac{R}{5KRC - K}} & \text{Distributed the -1}\\\end{array}[/tex]

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