Answer: The value of a should be 3.11.
Step-by-step explanation:
Since we have given that
[tex]9x-14y=-3\\\\2x-ay=-6[/tex]
We need to find the value of a so that it would yield a system of linear equations with NO solutions.
As we know the condition of no solutions, it means the lines should be parallel.
i.e.
[tex]\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}\neq \dfrac{c_1}{c_2}[/tex]
Consider the first two terms:
[tex]\dfrac{9}{2}=\dfrac{-14}{-a}\\\\a=\dfrac{2\times 14}{9}\\\\a=3.11[/tex]
So, the value of a should be 3.11.
