Chanman1221 Chanman1221
  • 04-03-2019
  • Mathematics
contestada

log3+logx-log(x+1)=log2

Respuesta :

Edufirst
Edufirst Edufirst
  • 04-03-2019

Answer:

  • x = 2

Step-by-step explanation:

These are the properties of logarithms that you have to use to solve the equation:

[tex]logA+logB=log (AB)\\ \\ logA-logB=log(\frac{A}{B} )[/tex]

[tex]logA=logB[/tex]⇒[tex]A=B[/tex]

With that you can follow these steps and find the value of x:

[tex]log3+logx-log(x+1)=log2\\ \\\\ log\frac{3x}{x+1} =log2\\ \\ \\ \frac{3x}{x+1} =2\\ \\ \\ 3x=2(x+1)\\ \\ \\ 3x=2x+2\\ \\ \\ x=2[/tex]

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