02-12-2018
Mathematics

contestada

a number P is divided by 12, 15 and 18. In each case tge remainder is 5. Find the smallest value of P

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02-12-2018

Answer:

P = 185

Step-by-step explanation:

First find the lowest Common Multiple of 12, 15 and 18:-

12 = 2 * 2 * 3

15 = 3 * 5

18 = 2 * 3 * 3

LCM = 2* 2* 3 *3 * 5 = 180

So the answer is 185.

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