HananF445507 HananF445507
  • 03-11-2022
  • Mathematics
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How do I solve this? My math teachers key says that it is 1 but I’m not sure how he got that.

How do I solve this My math teachers key says that it is 1 but Im not sure how he got that class=

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JoyeA738283 JoyeA738283
  • 03-11-2022

Given:

[tex]\lim_{x\to-1}(\sqrt[3]{x}-\frac{2}{\sqrt[3]{x}})^5[/tex]

You need to substitute this value of "x" into the expression inside the parentheses, in order to evaluate the limit:

[tex]x=-1[/tex]

Then:

[tex]\lim_{x\to-1}(\sqrt[3]{-1}-\frac{2}{\sqrt[3]{-1}})^5[/tex]

By definition:

[tex]\sqrt[3]{-1}=-1[/tex]

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